Title says all
Thanks for your help
Title says all
Thanks for your help
sed 'g/^[!0-9]/d' file
or
grep -v "^[!0-9]" file
I guess it should be:
sed '/^[^0-9]/d' file
OR
grep -v "^[^0-9]" file
grep "^[0-9]" file
this not remove empty lines
sed '/^[^0-9]/d' file
more good way
sed -n '/^[0-9]/p' file