Deleting First 10 letters in a line

UNIX for Advanced & Expert Users
1

Hi,

Could any one of you let me know any simple Unix command for deleting first 10 letters of first line in unix?

Eg: 123456789ABC --Input

ABC--Output

Thanks

Sue

2

You mean CB? (1-9 is 9 chars, not 10)

echo "123456789ABC" | sed 's/^..........//'
3

Hi,

Thank you. It worked when i use the code provided by you. Suppose if i need to use that code for a file and if i want to replace the input file with the first 10 letters removed, how can i do that?

Thanks

Sue

4 
sed 's/^..........//' inputfile > newfile
5

Hi,

If i do like that, i am getting an output file with 0 bytes.:frowning:

Please adivice me what can be done to resolve this.

Thanks

Sue

6

Hmm, but that is not very flexible, imagine the next problem being to remove the first 43 characters. How about:

echo "123456789ABC" | cut -c11-
7

Hi,

The following command gave me the correct results:

cut -c39- In_Put.txt > Out_Put.txt

Thanks Once again,

Sue

8

My output is:

-----------------------------

Now run:

My output is:

in testB

9

For deleting first n number of chars, instead of writing 'n' dots(.), following pattern can be used -

^.\{n\}
so the sed can be changed to

cat testA |sed 's/^.\{n\}//' > testB

10

if you want to change all the file name as u required then this might help u

ls | while read file
do
file_req=`echo ${file} | sed 's/^.\{n\}//' `
mv ${file} ${file_req}
done
:b: