delete lines in file matching a pattern

I have a text file, a sample of which is as follows:

r/- * 0:        WINDOWS/Microsoft.NET/Framework/v2.0.50727/ASP.NETWebAdminFiles/Images/headerGRADIENT_Tall.gif
r/- * 0:        WINDOWS/SoftwareDistribution/Download/cf8ec753e88561d2ddb53e183dc05c3e/backoff.jpg
r/- * 0:        WINDOWS/SoftwareDistribution/Download/cf8ec753e88561d2ddb53e183dc05c3e/but3_up.gif
r/- * 0:        WINDOWS/SoftwareDistribution/Download/cf8ec753e88561d2ddb53e183dc05c3e/merlin.gif
r/- * 0:        WINDOWS/SoftwareDistribution/Download/cf8ec753e88561d2ddb53e183dc05c3e/newtop8.jpg
r/- * 0:        WINDOWS/SoftwareDistribution/Download/cf8ec753e88561d2ddb53e183dc05c3e/venice.jpg
r/r * 73487-128-3:      WINDOWS/SoftwareDistribution/Download/cf8ec753e88561d2ddb53e183dc05c3e/backup.jpg
r/r * 73493-128-3:      WINDOWS/SoftwareDistribution/Download/cf8ec7523e88561d2ddb53e183dc05c3e/btn1.gif
r/r * 73494-128-3:      WINDOWS/SoftwareDistribution/Download/cf8ec753e88561d2ddb53e183dc05c3e/btn2.gif
r/r * 73495-128-3:      WINDOWS/SoftwareDistribution/Download/cf8ec753e88561d2ddb53e183dc05c3e/btn3.gif
r/r * 73496-128-1:      WINDOWS/SoftwareDistribution/Download/cf8ec753e88561d2ddb53e183dc05c3e/bullet1.gif

How do I remove those lines whose 3rd column is "0"?

TIA.

awk -F'( |:)'  '$3!=0' file > newfile

try this

awk -F"[*:]" '$2 != 0{print}' file_name > new_file