Define Positional Parameter Range Awk

Shell Programming and Scripting
1

Hello All,
I am trying to clean up a poorly looking awk command. I am searching for a way to define a range of positional parameters. I may not be searching for the correct syntax.

Example:

awk ' /14:3*/  {print $2,$3,$4,$5,$6,$7,$8,$9,$10,$11,$12,$13}' app.log

Is it possible to shorten with a range of some kind:

awk ' /14:3*/  {print $2........$13}' app.log

Thanks for your time.

Jaysunn

2

you can use loop.

awk '/14:3*/{for (i=2;i<=13;i++){printf "%s ",i}}END{print "\n"}' app.log
3

This gives me:

[root@server jason]# awk '/14:3*/{for (i=2;i<=13;i++){printf "%s ",i}}END{print "\n"}' app.log 
2 3 4 5 6 7 8 9 10 11 12 13 2 3 4 5 6 7 8 9 10 11 12 13 2 3 4 5 6 7 8 9 10 11 12 13 2 3 4 5 6 7 8 9 10 11 12 13

How do I specify the positions? I assumed it needs $n.

Thanks for your reply.

Jaysunn

4

Sorry, It should be

awk '/14:3*/{for (i=2;i<=13;i++){printf "%s ",$i}}END{print "\n"}' app.log
5 
awk '/14:3*/{for (i=x-1;i++<y;){printf $i ((i<y)?FS:RS)}}' x=2 y=13