What will the below statement do ?
[ -z "$VAR" ] &&
{
[ -x "/bin/setup" ] && {eval `/bin/setup 1`} || [ -d "/tmp/" ] && { VAR="/tmp" }
export $VAR;
}
Read about
man test
[ -z "$VAR" ]
check the $VAR is empty or not
-z string True if the length of string string is zero.
[ -x "/bin/setup" ] -- if it is empty, then check whether /bin/setup is having the execute permission for that user
If the user has execute permission, then execute the setup file with argument 1
If the user didnt have the execute permission, then check whether we have a directory called /tmp [ -d "/tmp/" ] and if it is there, then set the VAR variable value as /tmp
and export it
---------- Post updated at 03:39 PM ---------- Previous update was at 03:36 PM ----------
for && ||
example is
if [ condition ] then
echo "True"
else
echo "False"
fi
can be write like below
[ condition ] && echo "True" || echo "False"
With that
export $VAR
It'll likely break is what it'll do. It should simply be: export VAR
Thanks for the replies, I got this now 
