Date variable in shell script

Shell Programming and Scripting
1

Hello guys n girls,

I am using ksh script on AIX platform.
I am getting a DATE from input file in "YYYYMMDDHHMISS" format.
Now I want the same date in "YYYYMMDD" format into another variable.

For example,
if the DATE is 20101018121445
then I need 20101018 in another variable.

Please let me know the command to do it.
Thanks in advance.

2

On solaris on command line below date command gives 20101018, on AIX you can check the manual page of date cmd.

date '+%Y%m%d'
3 
$ DATE=20101018121445
$ DATE2=`echo $DATE | cut -c1-8`
$ echo $DATE2
20101018
1 Like
4

Something like this,

new_dt=$(echo "20101018121445" | cut -c1-8);echo $new_dt
5 
DATE=`date +%Y%m%d%H%M`
NEW_DATE=`echo ${DATE:0:8}`
6

This will work in any POSIX shell:

date=20101018121445
yyyymmdd=${date%??????} ## remove the last six characters

In bash and ksh93 you can do:

yyyymmdd=${date:0:8}
7

Thank you so much for your time and reply.