Cut line from file till the end

Shell Programming and Scripting
1

Hi
I have a 57 line text file and I want to cut first 6 line assigned it to a veriable and again cut next 6 line assigned to same variable till the time file have left 0 line.

Please let me know how I can do in scripting.

Thanks

Sanjay

2

We want to help you if you have shown that you have put some effort into solving your own problem but not to do your work for you.

3

hi

my original file /var/tmp/img-bkp1

head -6 /var/tmp/img-bkp1 >/var/tmp/used
grep -v -f /var/tmp/used /var/tmp/img-bkp1 >/var/tmp/unused.1
head -6 /var/tmp/unused.1 >/var/tmp/used
grep -v -f /var/tmp/used /var/tmp/unused.1 >/var/tmp/unused.2
head -6 /var/tmp/unused.2 > /var/tmp/used
grep -v -f /var/tmp/used /var/tmp/unused.2 >/var/tmp/unused.3

and so on

can you please tell me how put in loop so that file have left 0 line

4

try this..

 
for i in 1 7 13 19 25 31 37 43 49 55
do
  plus_six=`echo $i + 6 | bc`
   sed '"$i","$plus_six"p' filename >/var/tmp/output$i.txt
done
5

use split command to split the file

split -l 6  /var/tmp/img-bkp1

this will create the xx* file names in the same directory

you can read each one like

for i in xx*
 
do
 
---
done

Please refer to man pages on split also

6

try this..

% split -6 input_file; ls -1 x* | awk ' { print $0"_1=`cat "$0"`;" } ' | sh
7

Could you please tell us more about your final goal ?

a) How does the content of you input file look like ?
b) Why do you need lines 6 per 6 ?
c) What kind of processing do you run on them ?
d) What kind of output do you expect ?