Cut Last 3 Fields

Shell Programming and Scripting
1

I have a text:

dsj khfksjdh <time> EST 2006
ab cgnr jkkjt <time> EST 2006
gfhdgjghg <time> EST 2006
fkdjh kjhsekjrh kdjhfkh jhdfkhfdkjh kjdf <time> EST 2006

In the above file i need to extract time from every line... which is always the third from the last... Pls help!

Cheers,
Bouren

2

If you want only the third from the last field, this should work:

awk '{print $(NF-2)}' file

If you want the last three fields, try:

awk '{print $(NF-2), $(NF-1), $NF}' file
3

cat <filename>|awk '{print $(NF-2)}'

4

Useless Use of Cat

5 
sed "s/.*\(<time>.*\)$/\1/" file