Cut display multiple lines of output

Shell Programming and Scripting
1

I have a script that runs a command, and the output is on multiple lines. The fields are delimited by '='. I need the 8th column from the first line and the 2nd from the second line, but I can't figure out how to display the second line.

command1 | cut -d '=' -f 8

The above gets me what I need from the first line, but is there a way I can then get the second line information without having to re-run the command1?

My output is similar to the following:

test= foo=test=someinfo=moreinfo=testing again=misc info=First Column I need
randomInfo=Second Column I need

Example below:

>cat tmp.txt
test= foo=test=someinfo=moreinfo=testing again=misc info=First Column I need
randomInfo=Second Column I need

>cat tmp.txt | cut -d '=' -f 8
First Column I need

>cat tmp.txt | cut -d '=' -f 8-
First Column I need

The second one I tried to tell it to get everything from 8 until the end of the file, but it appears that cut views each line as a separate file maybe

2

Try awk

awk -F= '{a=$NF;getline;print a,$2;exit}'  file
3

Worked. Thank you.