cut a specific value from a column

Dear Friends,

I have an output like this:

7072;0;7072901
7072;1001;7072902
7072;101;7072903
7072;102;7072904
7072;1101;7072905
7072;1301;7072906
7072;1401;7072907
7072;162;7072908
7072;1;7072909

and I need to print the value in the column 3 , row number 1. which is 7072901 only. please:)

awk -F";" 'NR == 1 { print $3 }' your-filename

>head -1 myfile | cut -d";" -f3