Gents,
It is possible to generate a range of values according to column 1 and count the total of rows in the range.
example
input
15.3
15.5
15.8
15.9
16.0
16.1
16.8
17.0
17.5
18.0
output desired
15.0 - 15.9 = 4
16.0 - 16.9 = 3
17.0 - 17.9 = 2
18.0 - 18.9 = 1
Thanks for your help.
Yes. It is possible.
What operating system are you using?
What shell are you using?
What have you tried to solve this problem?
Please, give it a try.
perl -nle '++$r{int($_)}; END{for(sort keys %r){print "$_.0 - $_.9 = $r{$_}"}}' jiam912.input
Output:
15.0 - 15.9 = 4
16.0 - 16.9 = 3
17.0 - 17.9 = 2
18.0 - 18.9 = 1
Hi Don
The OS Debian 7
The Shell /bin/bash
I try
awk '{a[$1]++}END{for(i in a) print i, a }' file
It is only to count..
---------- Post updated at 08:18 PM ---------- Previous update was at 08:16 PM ----------
Aia
Thanks a lot
---------- Post updated at 08:18 PM ---------- Previous update was at 08:18 PM ----------
Aia
Thanks a lot
---------- Post updated at 08:18 PM ---------- Previous update was at 08:18 PM ----------
Aia
Thanks a lot
---------- Post updated at 08:18 PM ---------- Previous update was at 08:18 PM ----------
Aia
Thanks a lot
---------- Post updated at 08:18 PM ---------- Previous update was at 08:18 PM ----------
Aia
Thanks a lot
---------- Post updated at 08:18 PM ---------- Previous update was at 08:18 PM ----------
Aia
Thanks a lot
With a bit of modification to yours:
awk '{a[int($1)]++}END{for(i in a) print i".0 - "i".9 =", a}' input.file | sort -n
Aia.. Thanks a lot for your help
---------- Post updated at 05:38 AM ---------- Previous update was at 12:19 AM ----------
Please can you modify a little the code to use this input.
1 15.3
1 15.5
2 15.8
2 15.9
3 16.0
3 16.1
4 16.8
4 17.0
5 17.5
6 18.0
1 18.0
10 17.1
to get this output.
15.0 - 15.9 16.0 - 16.9 17.0 - 17.9 18.0 - 18.9
1 2 0 0 1
2 2 0 0 0
3 0 2 0 0
4 0 2 0 0
5 0 0 1 0
6 0 2 0 1
10 0 0 1 0
Please if is possible to use awk..
Appreciate your help
Hint: use a two-dimensional array to store the data, and two nested loops to print them.
RudiC,
I will try
Hi, I am trying to use this code to solve the problem but it does not work. 
awk '{if(!X[$1]++){FIR=FIR?FIR"_"$2:$2} {Y[$1]=$1;Z[$2]++}}END{n=split(FIR,FCL,"_");for(i=1;i<=n;i++){s=s?s"\t"FCL:"\t"FCL} print s; for(j in Z){s=j;for(i=1;i<=n;i++){split(FCL,PK," ");p=Y[PK[1],PK[2],j]?Y[PK[1],PK[2],j]:0;s=s"\t\t"p};print s}}'
---------- Post updated at 06:51 AM ---------- Previous update was at 06:49 AM ----------
input
1 15.3
1 15.5
2 15.8
2 15.9
3 16.0
3 16.1
4 16.8
4 17.0
5 17.5
6 18.0
1 18.0
10 17.1
output desired
15.0 - 15.9 16.0 - 16.9 17.0 - 17.9 18.0 - 18.9
1 2 0 0 1
2 2 0 0 0
3 0 2 0 0
4 0 2 0 0
5 0 0 1 0
6 0 2 0 1
10 0 0 1 0
Hmmm - try
awk '
{A[$1]
B[int($2)]
C[$1,int($2)]++
}
END {for (b in B) printf "\t%d.0 - %d.9", b, b
printf ORS
for (a in A) {printf "%s", a
for (b in B) printf "\t%d", C[a,b]
printf ORS
}
}
' file
15.0 - 15.9 16.0 - 16.9 17.0 - 17.9 18.0 - 18.9
10 0 0 1 0
1 2 0 0 1
2 2 0 0 0
3 0 2 0 0
4 0 1 1 0
5 0 0 1 0
6 0 0 0 1
Thanks a lot RudiC