converting unix timestamp into readable format using c++

Applications Programming
1

hi everyone, im new here and am in desperate need of help. I want to convert my 32 bit unix time stamp ' 45d732f6' into a readable format (Sat, 17 February 2007 16:53:10 UTC) using c++.

I have looked around the interent but i just cant make sense of anything. All examples i can find just get the current date and time they dont actually show you how to take an actual timestamp and convert it.

I really hope you guys can help me, im not a great programmer and would greatly appreciate an example or some guidence as to how to proceed

thank you

2

If you know how the date and time has been encoded in the 32-bit hexadecimal string '45d732f6' then it's possible to come up with something that makes sense :confused:

3

Since you did not provide feedback I tried to figure it out myself. The hex string is the seconds from the UNIX epoch and translates to Sat 17 February 2007 16:53:10 UTC

#include <stdio.h>
#include <time.h>

main(void)
{
    time_t epch = 0x45d732f6;
    printf("0x%x -> %s", epch, asctime(gmtime(&epch)));
}
4

im sorry for my late reply shamrock. Thank you for your input it has been very helpful in my program!!

thanks again!