Hi guys, i need your help.
I need to convert a date like this one 20071003071023 , to a formated date
like 20071003 07:10:23 .
Could this be possible ?
Regards,
Osramos
Hi guys, i need your help.
I need to convert a date like this one 20071003071023 , to a formated date
like 20071003 07:10:23 .
Could this be possible ?
Regards,
Osramos
# echo "20071003071023" | awk '{print substr($0,1,8)" "substr($0,9,2)":"substr($0,11,2)":"substr($0,13,2)}'
20071003 07:10:23
echo 20071003071023 | sed 's/\(..\)\(..\)\(..\)$/ \1:\2:\3/'
Hello,
thanks to all who help me, but i make a mystake .
I've got this piece of file
APPLICATION GROUP_NAME MEMNAME ODATE STATUS START_TIME END_TIME
-------------------- -------------------- ------------------------------ ------ ---------------- -------------- --------------
AFT AFTSCMDIVD AFTDIVD1312A 071001 Ended OK 20071002041242 20071002041242
AFT AFTSCMDIVD AFTDIVD0115B 071002 Ended OK 20071003063253 20071003063303
and i want to convert to this :
APPLICATION GROUP_NAME MEMNAME ODATE STATUS START_TIME END_TIME
-------------------- -------------------- ------------------------------ ------ ---------------- -------------- --------------
AFT AFTSCMDIVD AFTDIVD1312A 071001 Ended OK 20071002 04:12:42 20071002 04:12:42
AFT AFTSCMDIVD AFTDIVD0115B 071002 Ended OK 20071003 06:32:53 20071003 06:33:03
like i've told before , all i need is to format the date and time, but i need to have also the file output with all de information.
Is it possible or is more complicated
Have you tried the sed command I provided? It will format the last occurrence, you can easily extent that to cover the date in the second to last field.
Hi, yes i have tried with you sed command like this :
cat report_jobs_CTM.csv | awk '{print $7 $8}' |sed 's/\(..\)\(..\)\(..\)$/ \1:\2:\3/' > new.csv
but the the result was this:
EN D_:TI:ME
-------- --:--:--
2007100204124220071002 04:12:42
2007100204124820071002 04:12:48
Why i am doing wrong ?
awk '{
for(i=7;i<=8;i++) {
$i=substr($i,1,8)" "substr($i,9,2)":"substr($i,11,2)":"substr($i,13,2)
}
{print}
}' "file"