Conversion of line via awk or etc

Hello friends, could you help me about problem with my data lines. I suppose a simple awk code may help me.

I have following data lines: (first line including 3 numbers and then a matrices of 4x10)

           500  40  9
 1  A  B   4   5  6   7   8   9 10
11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30
31 32 33 34 35 36 37 Z P R

How can I convert this format to

first line sum of 3 numbers at the first line ---> 549
second line is converted to 1x40 ----> 1 A B 4 5 6 7 8 9 ..... Z P R

Could anyone help ?

thanks

awk ' BEGIN { sum=0; }
 NR==1 { for(i=1;i<=NF;i++) { sum+=$i; } print sum; }
 NR>1 { for(i=1;i<=NF;i++) printf "%s ", $i }
 END { printf "\n";
} ' filename

thank you very much bipinajith ,

what if I have multiple as follows, is it possible to do each of them seperately

            5  2  3
 -12.108 -11.789  -5.196  -4.370  -3.344  -2.229  -1.465  -0.347  -0.325   2.456
   2.855   4.105   4.569   5.902   7.791   7.950   8.750   9.383  10.041  10.160
  10.755  11.441  11.827  12.302  12.847  13.816  15.849  15.904  16.213  16.383
  17.158  17.705  18.715  19.221  19.330  19.411  19.696  20.122  20.142  20.417
            7  4  8
 -12.118 -11.796  -5.181  -4.356  -3.345  -2.225  -1.463  -0.351  -0.334   2.454
   2.842   4.093   4.566   5.937   7.785   7.924   8.741   9.360  10.046  10.129
  10.845  11.461  11.850  12.233  12.942  13.811  15.853  15.860  16.200  16.399
  17.192  17.707  18.708  19.149  19.302  19.381  19.664  20.017  20.089  20.375

I mean

            11
 -12.108 -11.789  -5.196  -4.370  -3.344  -2.229  -1.465  -0.347  -0.325   2.456  2.855   ....
            19
 -12.118 -11.796  -5.181  -4.356  -3.345  -2.225  -1.463  -0.351  -0.334   2.454  2.842  ...

is it possible ?

Assuming every new set starts with 3 numbers:-

awk ' BEGIN { sum=0; }
 NF==3 { for(i=1;i<=NF;i++) { sum+=$i; } if(NR==1) printf "%s\n", sum; else printf "\n%s\n", sum; sum=0;}
 NF>3 { for(i=1;i<=NF;i++)  { printf "%s ", $i; } ; }
 END { printf "\n";
} ' filename

Thank you very much... It works perfect.

One last question. If you don"t have time forget it

instead of simple sum of 3 numbers i.e. a+b+c, is it possible to get Sqrt(axa+bxb+cxc) with this code ?

which part should I change ?

thank you for your time

You have to change 2nd line to:

 NF==3 { for(i=1;i<=NF;i++) { sum+=($i*$i); } if(NR==1) printf "%s\n", sqrt(sum); else printf "\n%s\n", sqrt(sum); sum=0;}

thanks bipinajith
It works perfect...

thank you for your time