Hi Gurus,
Need help in Conversion of date(2007-11-30) to Julian date(YYDDD)...
'+%J'
2007-11-30 to 'YYDDD'
Thanks
check out the FAQ article on this site....
http://www.unix.com/answers-frequently-asked-questions/13785-yesterdays-date-date-arithmetic.html
you should find what you're after in there - this type of question comes up regulalrly enoiugh that searching the forums (or checking the above article) should be enough...
If you're still having problems, post your code/attempts and we'll see what we can do 
Thanks ..
---------- Post updated at 09:30 PM ---------- Previous update was at 07:24 PM ----------
# your date
DATE="2007-11-30"
DATE=`echo $DATE | sed 's/-//g'`
date --date=$DATE '+%y%j'
throws an error
date: illegal option -- -
Usage: date [-u] [+format]
date [-u] [mmddhhmm[[cc]yy]]
date [-a [-]sss.fff]
install GNU date
$ date -d "2007-11-30" +%j
334
is there any other way
to get the date(2007-11-30) to Julian date(YYDDD)...