concatenating the filenames in a directory

Shell Programming and Scripting
1

hi all,

I have a requirement where in i have to read all the filenames based on a pattern from a directory and concatenate all these file names and write it to another file.

i am using the following code to do this

var1=''
for filename in $_DIR/${FILE_NAME}*
do
if
if [ X${var1} = "X" ]
then
var1=$var1$filename
else
var1=$var1:$filename
fi

done

`echo "$var1"` >> $DIR/$filename_out.txt

its taking really long time to execute this script if there are more number files matching the pattern.

can any one suggest a better appraoch, than above one?

Thanks,
Narendar

2

pattern="xyz"
ls | grep "$pattern" > file_out.txt

3

this will add the files matching the patter to the file_out..

but i want them to concatenated using ":" and added.

4

What the heck does concatenated mean. Provide an example of what you want to do.

5

I did something similar using the current date (fetching Status pages from my cable modem). Don't know if this will help you:

CUR=`date | sed 's/\ /_/g'`.asp
wget http://192.168.100.1/Status.asp
mv Status.asp $CUR
6

for the heck...i want the output to be in the form
DIR/filename: DIR/filename2: DIR/filename3: DIR/filename4..so on to be added to the output file.

[space between : and DIR is not required but the webpage was converting it to a smiley :D. so i have kept the space. in original output that space is not required]
where filename[1-4]..files matching the pattern 'filename' in the DIR

as i mentioned i was able to do this..but just wanted to know if there is any better way to do this....

7

If you don't mind the colon at the end of the line use:

$ dir=test
$ FILE_NAME=html

$ printf "%s:" `ls -p $dir/${FILE_NAME}*|grep -v '/$'` 

$ test/html_1:test/html_2:test/html_3:

removing the last colon:

$ printf "%s:" `ls -p $dir/${FILE_NAME}*|grep -v '/$'` | sed 's/:$//'
8

Thank you all for the responses!!!

I am using the following query

var1=$( printf ":%s" "$DIR/${FILE_NAME}"* )
printf "%s\n" "${var1#?}" >> "$DIR/$filename_out.txt"

Thanks,
Narendar