Comparing current date

Shell Programming and Scripting
1

Hi,

I have start date and end date in the following format. I need to check the current date is greater than the start date and less than the end date. if i use the command date --date "Tue 6:00 AM", it takes next Tues day not the current week's Tues day. Is there a way to get the current Tues day?
start date-end date
Tue 6:00 AM-Wed 10:00 PM

Thanks,
Selva

2

Try:

date --date 'Tue 6:00 AM 1 week ago'

BTW: Works only with the GNU version of date.

3

If i run the process on Tuesday, it will take previous week date instead of current Tues day. I need to get current week date.

Thanks.

4

Is this not what you want?

$ date --date 'Tue 6:00 AM'
Tue Nov  9 06:00:00 CET 2010
$
$ date --date 'Tue 6:00 AM 1 week ago'
Tue Nov  2 06:00:00 CET 2010
$
5

No. I need to check the current date is between the start date or not. If i run the command with 1 week ago, the start date will be Tue Nov 2 06:00:00 EDT 2010
but End date will be Wed Oct 27 22:00:00 EDT 2010 which wrong. I hope that i am making you clear.

Thanks,
bharathappriyan

6

Play around with this example:

#!/bin/ksh

# Works only with GNU date

d1="Tue Nov 02 22:00:00 EDT 2010"
d2="Fri Nov 05 22:00:00 EDT 2010"
cdate=$(date)

dat1=$(date +%s -d "$d1")
dat2=$(date +%s -d "$d2")
curr=$(date +%s -d "$cdate")

if [ $curr -gt $dat1 -a $curr -lt $dat2 ]
then
  echo Current date is between "$d1" and "$d2"
fi
7

How about replace Tue (current day) with blank giving "6:00am":

START="Tue 6:00 AM"
END="Wed 10:00 PM"
DOW=$(date +%a)
START=${START/$DOW/}
END=${$END/$DOW/}
NOW=$(date +%s)
if [ $NOW -ge $(date --date $START +%s) -a $NOW -le $(date --date $END +%s) ]
then
   # Your code here
fi

I know if today is Thursday the compare is with next weeks dates, but that's fine as result (not within range) is still what you want.

--- Edit----
But my solution still dosn't work for Mon 8:00AM-Thu 9:00PM, problem is you can't apply the DOW modifiers to any date except the current date.
What we need is date --date "Monday 9:00AM from 6 days ago"

8 
$
$
$ echo "Tue 6:00 AM-Wed 10:00 PM" | perl -lne 'BEGIN {%dow=qw(Sun 0 Mon 1 Tue 2 Wed 3 Thu 4 Fri 5 Sat 6)}
           /^(\w+)\s*(\w+):(\w+)\s*(\w+)-(\w+)\s*(\w+):(\w+)\s*(\w+)$/;
           $smin = $2*60+$3+($4 eq "PM" ? 12*60 : 0);
           $emin = $6*60+$7+($8 eq "PM" ? 12*60 : 0);
           @x = localtime;
           if ( ($x[6] < $dow{$1}) or
                ($x[6] == $dow{$1} and ($x[2]*60+$x[1]) < $smin) or
                ($x[6] > $dow{$5}) or
                ($x[6] == $dow{$5} and ($x[2]*60+$x[1]) > $emin)
              ) {
             print "Current date/timestamp is outside the range => $_"
           } else {
             print "Current date/timestamp is within the range => $_"
           }'
Current date/timestamp is within the range => Tue 6:00 AM-Wed 10:00 PM
$
$
$

tyler_durden

9

OK here is a bash/ksh script that does it (again you need GUN date for the --date function).

I defined a function thisweek() that returns the epoch time of a string like "Tue 09:00AM", once that's done the rest is a simple numeric comparison.

inrange:

DOW_TODAY=$(date +%u)
thisweek()
{
  DOW=$(date --date "$1" +%u)
  [ $DOW -lt $DOW_TODAY ] && date --date "${1}-7days" +%s && return
  date --date "${1}" +%s
}
 
END=${1#*-}
START=${1%-*}
NOW=$(date +%s)
if [ $NOW -ge $(thisweek $START) -a $NOW -le $(thisweek $END) ]
then
   echo "In range"
else
   echo "Not in range"
fi

Here are some tests:

$ inrange "Mon 01:00AM-Fri 09:00PM"
In range
 
$ inrange "Mon 01:00AM-Tue 01:00AM"
Not in range
 
$ inrange "Thu 11:00PM-Fri 11:00PM"
Not in range
 
$ inrange "Yesterday 11PM-3PM"
In range
10

Hi,

Thanks a lot for your code. Let me try and see.

Thanks,
bharathappriyan