I am trying to compare two lists that are held in two variables so I believe I need to access the array elements to compare these. I am using ksh 88 and the code I have tried is below:
for file in ${origfilelist}
do
if [[ "${file}" != $failfiles[@] ]]
then
print -- "File ${file} not found "
else
print -- "File ${file} found"
fi
done
Unfortunately all are being flagged up as 'not found' when I know there are some of the same filenames in both variables.
#!/usr/bin/ksh
A="1 2 3 4"
B="5 6 2 7"
for a in $A; do
for b in $B; do
(( $a == $b )) && print $a
done
done
exit 0
For arrays you'll have to declare them with set -A ..... and cycle through their elements by incrementing the index. Though it would be most likely 2 loops in each other like the example above.
Update:
Here an example with an array without incrementing the indexes and comparing strings instead of numbers.
But when there is no need for indexes, maybe a list will be sufficient instead of arrays. But when having spaces in file names it might be easier to use them as array elements than in a list (depending how the separator IFS is defined and used in the list of course).
#!/usr/bin/ksh
set -A ARR1 1 2 3 4
set -A ARR2 5 6 2 7
for a in ${ARR1[*]}; do
for b in ${ARR2[*]}; do
[[ "$a" = "$b" ]] && print $a
done
done
exit 0
Thanks. The nested for loop works but if I want to output files that arent found as well I get repeated messages due to not matching to any of the array elements, how could I only output the filenames that arent found just once? I guess I could put them into another variable and then use the uniq command maybe?
for orig in ${origfilelist}
do
for fail in ${failfiles}
do
if [[ ${orig} == ${fail} ]]
then
print -- "File ${orig} found "
else
print -- "File ${orig} not found"
fi
done
done
Thanks
p.s I though all variables were arrays?
---------- Post updated 30-01-13 at 09:17 AM ---------- Previous update was 29-01-13 at 01:11 PM ----------
Although I still would like the answer to the previous question I also need to know how to output the array elements onto different lines in a text file?
Here is an example how you could cycle and compare array elements (example with integers) and print only those from array 1, which are not in array 2:
$ cat ./mach.ksh
#!/usr/bin/ksh
set -A ARR1 4 1 3 2
set -A ARR2 5 6 2 7 4 8
MAX=$((${#ARR2[*]}-1))
for a in ${ARR1[*]}; do
COUNT=0
set -A HITS
for b in ${ARR2[*]}; do
(( $a != $b )) && \
HITS[$COUNT]=$a && \
let COUNT+=1
done
(( ${#HITS[*]} != $MAX )) && \
print ${HITS[0]}
unset HITS
done
exit 0
$ ./mach.ksh
1
3
Somehow there is a blank line at the end. Didn't find where it comes from
Maybe other people have more efficient algorithm to do this which would be interessting for me too.
If you have 2 files with the lists of files you might want to compare, a grep -f file1 file2 or grep -vf file1 file2 might be more efficient than my example.
