combine multiple finds into 1-liner

Shell Programming and Scripting
1

How to combine 3 find statements into 1-liner?

find statements:

cd ${dir1} ; find . ! -name . -prune -type f | xargs file | grep -i ascii | cut -f1 -d: | xargs grep -l "${searchtxt}"
cd ${dir2} ; find . ! -name . -prune -type f | xargs file | grep -i ascii | cut -f1 -d: | xargs grep -l "${searchtxt}"
cd ${dir3} ; find . ! -name . -prune -type f | xargs file | grep -i ascii | cut -f1 -d: | xargs grep -l "${searchtxt}"

pls advise and thanks in advance.

2 
find "$dir1" "$dir2" "$dir3"  ! -name . -prune -type f | xargs file | grep -i ascii | cut -f1 -d: | xargs grep -l "${searchtxt}"

Should work.
No need to quote if you're sur there are no blanks in dir names.

3

doesn't work :frowning:

4

Do you have any idea how unhelpful that kind of response is?

What doesn't work?

The command, such as it is, works fine for me.

5

the proposed find statement below doesn't work as expected:

find "$dir1" "$dir2" "$dir3"  ! -name . -prune -type f | xargs file | grep -i ascii | cut -f1 -d: | xargs grep -l "${searchtxt}"

no output from the above statement. this is because when dirs are specificied in the find, the statement couldn't find name "." which is not pruned.