Can any body give me a solution to this...

Shell Programming and Scripting
1

Hi friends..
I am using the below command to search few files from many folders which is under one folder..

i mean let say the path is A/B/C...and inside C...i have 1-10 folder...

the below command is working fine....

for i in 1 3 5 7; do
find /A/B/C/${i} -name ".txt" -o -name ".csv" -o -name ".TXT" -o -name ".dat" |xargs ls -ltr |awk '{print $8 ,$9}' >> ${i}.txt
done

this will give me the result from the folder 1 3 5 7 ,from 1-10 which is inside A/B/C[/b] and print the file having the above extension into 1.txt , 3.txt , 5.txt , 7.txt etc inside /A/B/C

Help needed..

i need some help so that my syntax will search the file only from folder 1,3,5,7 from the 10 folder A/B/C and the out put from these 4 folder will be display in the single file i.e result.txt....not in different folder.

the above 1,3,5,7 folders are inside A/B/C

2

see also on other time...
http://www.unix.com/shell-programming-scripting/73107-can-you-please-help-me-out.html\#post302214206

You know, if you don't understand the response, or it is taking you in a direction that will not work for you, pose the question differently or something.

3

thats true..Could you please help me out on this...could you plse give me the solution for this...

for i in 1 3 5 7; do
find /A/B/C/${i} -name ".txt" -o -name ".csv" -o -name ".TXT" -o -name ".dat" |xargs ls -ltr |awk '{print $8 ,$9}' >> result.txt
done

it giving me result in result.txt as ...below..

1
3
5
7

i mean the folder name.. but if i am using ${i}.txt then its give me in separate file..not in a single file......

4

I have read all three posts and answers, but still do not understand what you have and/or what you want. Try a different approach to describe it.

/root
 /A
  /1.txt
  /3.dat
  /B
   /2.txt
   /C
    /1.txt
    /3.dat
    /5.TXT
 /AA
  /2.dat
  /3.dat
  /5.TXT
 /AAA
  /7.TXT

need a file containing...
>>>describe it here....

5

i mean let say the path is A/B/C...and inside C...i have 1-10 folder...

i need to find the different file type from different folder and to print those results in single out file..

for i in 1 3 5 7; do
find /A/B/C/${i} -name ".txt" -o -name ".csv" -o -name ".TXT" -o -name ".dat" |xargs ls -ltr |awk '{print $8 ,$9}' >> ${i}.txt
done

this give me output in 1.txt , 3.txt , 5.txt , 7.txt..

but i need the result in one file let say result.txt...if am putting result.txt in plase of ${i}.txt then i am getting result in result.txt as below

1
3
5
7

but here i need the file which contains in these folder 1,3,5,7 and print in result.txt....

6

or let say...

A/B/C/1 2 3 4 5 6 7 8 9 10...

i mean inside C i have 10 folder..
in 1- a.txt
in 2- b.txt
in 3- c.txt
in 4- d.txt
in 5- e.txt
in 6- f.txt
in 7- g.txt
in 8- h.txt

the syntax should give me the result in result.txt from 1,3,5,7 folder is...
a.txt
c.txt
e.txt
g.txt

7

... too fast :slight_smile:

for i in `ls {1,3,5,7}/*.{txt,TXT,dat,csv} 2>/dev/null`;do echo ${i#*/} >> results.txt;done
8

What is the output with?

for i in 1 3 5 7; do
  find /A/B/C/${i} -name "*.txt" -o -name "*.csv" -o -name "*.TXT" -o -name "*.dat" 
done
9

thanks danmero..Frank many thanks....

for i in `ls {1,3,5,7}/.{txt,TXT,dat,csv} 2>/dev/null`;do echo ${i#/} >> results.txt;done
--------------------------------------------------------------------------------

but it will not find from all the folder....

10

.. awk -F'/' '{print $NF}' ....

i didnt get this...