Calculator

Shell Programming and Scripting
1

I am pretty new to the Unix word, and have created a working calculator script. I have one problem. It doesn't use any decimals, it rounds off to the nearest whole number.

  1 \#!/bin/ksh
  2 while true; do
  3    echo -n "Enter the first integer: "; read IN1
  4    test "$OP1" = "x" && exit 0
  5    echo -n "Enter an operator: "; read OPR
  6    test "$OPR" = "x" && exit 0
  7    echo -n "Enter the second integer: "; read IN2
  8    test "$OP2" = "x" && exit 0
  9    RES=$\(expr "$IN1" "$OPR" "$IN2"\)
 10    echo "Answer: $IN1 $OPR $IN2 = $RES";
 11 done;

Any ideas? Thanks.

2

Shell arithmetic is integers only, sorry.

3

Since Bash only recognizes normal integers, you can pipe the math through the 'bc' utility and it'll return float values.

RES=$(echo "$IN1" "$OPR" "$IN2" | bc)

Hope this helps.