batch shell script to zip individual files in directory - help

Shell Programming and Scripting
1

help trying to figure out a batch shell script to zip each file in a directory into its own zip file

using this code but it does not work

tryed this also

nothing seems to work , just ends without zipping any files

i have over 3000 files i need to zip up individualy

files to be zipped are in this format 123.flv.3gp

hopfully ending up like 123.flv.3gp.zip

is the file structure the problem

running a single zip command from shell seems to work ok

thanks for help in advance

2

The first script looks excellent, if you run it like 3gptozip *.3gp

3

sorry to be a bit stupid but how or what do i change and where to make this work
am i not doing the

zip -j "$f.zip" "$f"

part right

or is there a problem, in the echo commands

i was tying to run it with

nohup ./3gptozip.sh &

and

./3gptozip.sh

but is that the problem

thanks, i'm new to shell scripting by the way

4

The problem is that you need to list the files you want to zip on the command line, the script doesn't contain this information. "$@" contains the arguments passed to the script on the command line.

5

how whould i do that in shell ??

is it something like

nohup ./3gptozip.sh *.3gp &

or

./3gptozip.sh *.3gp

or is that the incorrect way to do it, thanks for help by the way

6

thanks works ok now

7

how to zip individual files (.txt) into its own zip file.
is it something like

directory name 'test'

for file in test/* do zip $file.zip $file.txt?
it's not working. please help.

8

for file in $(find ./test -type f);do zip ${file}.zip $file;done

use fine with the option '-type f' so you only find files and not directories.