Badly formed number.

Shell Programming and Scripting
1

I have the following script running every day numerous times a day and it works fine, but very occasionally I get the following error

if: Badly formed number.

Anyone know why?

Here is the script that runs with the follow parms

LCTMDBSE 100000 130000 160000

#!/bin/csh  
 
##############################
# Variables and Parameters   #
##############################
 
set JOBNAME=$0
set LOWNUM=$1
set MEDNUM=$2
set HIGHNUM=$3
 
##############################
# Validate Number of parms   #
##############################
 
if $#argv != 3 then
echo YOU MUST SUPPLY 3 PARAMETRES - LOW, MEDIUM AND HIGH VALUES 
exit 1
endif
 
###################################
# Validate Parms in correct order # 
###################################
 
if ( ( $HIGHNUM <= $MEDNUM ) || ( $HIGHNUM <= $LOWNUM ) || ( $MEDNUM <= $LOWNUM ) ) then
echo YOU MUST SUPPLY 3 PARAMETRES IN ASCENDING ORDER - LOW, MEDIUM AND HIGH VALUES
exit 2
endif
 
##############################
# Remove full path           #
##############################
 
set PATH_BREAKDOWN=`echo $JOBNAME | tr / " "`
foreach BARREL ( $PATH_BREAKDOWN )
   set REALJOBNAME=$BARREL
end
 
set JOBNAME=$REALJOBNAME
 
set  CMPROFILE=`whoami` 
 
##############################
# Run the SQL                #
##############################
 
set RESULT=`LCTMSQL count_dbase`
 
###################################
# Compare Results                 #
###################################
 
if ( "$RESULT" <= "$LOWNUM" ) then
echo Number of jobs on $CMPROFILE Database is $RESULT
echo This is classed as LOW
exit 0
endif
 
if ( "$RESULT" >= "$MEDNUM" && "$RESULT" < "$HIGHNUM" )  then 
echo Number of jobs on $CMPROFILE Database is $RESULT
echo This is classed as MEDIUM
exit 4
endif
 
if ( "$RESULT" >= "$HIGHNUM" ) then
echo Number of jobs on $CMPROFILE Database is $RESULT
echo This is classed as HIGH
exit 8
endif