awk value return

Shell Programming and Scripting
1

I have a script in awk and i have a unix shell script too ,and i want to call from the unix shell the awk script but that is returning a value according to what have been checked and found like boolean value in the awk script.
How do i do it?

2

It's not clear what you're trying to achieve, can you clarify your question with an example?

Regards

3

the usual way to execute an awk script is

awk -f awkscript filename

cheers,
Devaraj Takhellambam

4

#!/bin/sh
awk -f input_check.awk strings.txt \\here i want the input_check.awk script to return a value that is boolean to the value will be used after this line with a if condition
awk -f messview.awk messages
awk -f report_maker.awk warn.txt
i=1;
new="yes"
for file in `ls`
do
file_check="part"$i;
if [ "$file" = "$file_check" ]
then
if [ "$new" = "yes" ]
then
cat $file_check > "reporta.txt"
new="no"
else
cat $file_check >> "reporta.txt"
fi
rm $file_check
(( i = i+1 ))
fi
done

5

retval=`awk -f input_check.awk strings.txt`

Make sure you return either a 0 or 1 in your awkscript. Then you can test in your unix script for 0 or 1.

cheers,
Devaraj Takhellambam

6

But how can i return the value like this with awk?

7 
 print "0"

or

print "1"
8

To be more preciser, the above statements echo the return code on the screen. The way to get the return code with the above statements in your script is:

retval=`awk -f input_check.awk strings.txt`

To return an exit code you can use the exit statement of awk:

exit(ReturnCode)

The return code can then be retrieved with:

retval=`echo $?`
9

GNU nano 2.0.6 File: union.sh

#!/bin/sh
error=`awk -f input_check.awk strings.txt`
if [ "$error" = "ok" ]
then
awk -f messview.awk messages
awk -f report_maker.awk warn.txt
i=1;
new="yes"
for file in `ls`
do
file_check="part"$i;
if [ "$file" = "$file_check" ]
then
if [ "$new" = "yes" ]
then
cat $file_check > "reporta.txt" GNU nano 2.0.6 File: union.sh

#!/bin/sh
error=`awk -f input_check.awk strings.txt`
if [ "$error" = "ok" ]
then
awk -f messview.awk messages
awk -f report_maker.awk warn.txt
i=1;
new="yes"
for file in `ls`
do
file_check="part"$i;
if [ "$file" = "$file_check" ]
then
if [ "$new" = "yes" ]
then
cat $file_check > "reporta.txt"
new="no"
else
cat $file_check >> "reporta.txt"
fi
rm $file_check
(( i = i+1 ))
fi
done
fi

new="no"
else
cat $file_check >> "reporta.txt"
fi
rm $file_check
(( i = i+1 ))
fi
done
fi

I have this script now and the problem that if i want that the variable will get the value i need to do the command echo $error and then it prints the value of error too which i do not want to happen.
How can i avoid printing its value?

10

Don't confuse with the last replay ,i posted the script twice ,start reading from the second "#!/bin/sh"

11

In the case of the awk exit mode it allways returns 0 ,how can i make the script return a value like i want?

12

As Franklin52 mentioned,

exit somenumber  (in your awk script)
ret=`echo $?`

( in the shell script)

Can you paste your awk script also?

cheers,
Devaraj Takhellambam

13

BEGIN{ error="false";line=1;
}
{
check_count=split($0,count," ");
if (check_count<=3)
{
printf("Not enough sub strings in line %d should have method ,figures of row and count syntax and at least on$
error="true";
}
if ($1!="row"&&$1!="all")
{
printf("Bad name of words appearance metrhod on line %d, should be "all" or "row"\n",line);
error="true";
}
digits[1] = 0;
digits[2] = 0;
len[1] = split( $2, arr1 ,"" )
len[2] = split( $3, arr2 ,"" )
for ( i = 1; i <= len[1]; i++ )
if (( arr1 [i]+ 0 ) == arr1 [i])
digits[1]++
for ( i = 1; i <= len[2]; i++ )
if (( arr2 [i]+ 0 ) == arr2 [i])
digits[2]++
for (i=1;i<=2;i++)
{
if (i==1)
str="row";
else
str="all";
if ( len [i]!= digits[i]||digits[i]<0 )
{
printf("Invaild value for the %s field on line %d should be numeric and equal or great from 0\n",str,line);
error="true";
}
}
}
END {exit(error);
}

14

Don't use a literal "true" or "false" as a return value but a 0 for true and another number for false.