awk to parse df output

Shell Programming and Scripting
1

Output of the below code includes unmatched date.Please correct it

df -k|awk '$4>50 {print $1, "\t"$4,"\t" $7}'

It gives output less than 50% also.

2

Can you provide us the output of "df -k". I get available space as 4th column and the above code is working fine for me

3

yes it gives output to me also but it includes 40% used space in output as well for the above while expected is 50%+ only.

4

If you are sure about 4th field, use the below code

df -k | awk '{split($4, a, "%")} a[1] > 50 {print $1 "\t" $4 "\t" $7}'

If it is 5th field, change $4 to $5 in split function

5

Try

df -k | awk '$4+0>50{print $1, "\t"$4,"\t" $7}'
6

thanks all. Last 2 code snippet provided above works . Thanks again.