awk: setting decimal

Shell Programming and Scripting
1

hello,

when I type the following command

awk -v varc="$i"  '{ new=($1*varc)} { print new }'

it gives outputs in 5 decimal. How can I set my outputs to 9 decimal by using awk.

thanks

2

Hi.

Use printf instead of print.

i.e.

{printf "%.9f\n", new}

I imagine it only gives you 5 because that's all the precision there is?

1 Like
3

hi scottn thank you for your quick reply. My last question is that

for two variable, following line does not work

awk -v varc="$i"  '{ a1new=($1*varc); a2new=($2*varc)} { printf "%.9f\n, a1new" "a2new " }'

what is wrong ?

4

If you have two values you need two format parameters

{ printf "%.9f %.9f\n", a1new, a2new }
1 Like
5

it works. many thanks

6

or:

awk -v varc="$i" -v OFMT='%.9f' '{ a1new=($1*varc); a2new=($2*varc)} { print a1new, a2new}'