I need an awk script that returns the 1st field of the line in the middle of a file. For example, if a file I have has 6 lines, I want it to return the 1st field on line number 3. If a file has 7 lines, I want the script to return the 1st field on line number 4.
Sorry I'm not sure but maybe I didn't explain it clearly. I will only be doing this on one file at a time. I just listed 2 files as 2 separate examples. I tried using the code you put with one file and nothing showed up on the screen. Pardon my ignorance. Can you clarify?
Thanks!
---------- Post updated at 09:14 PM ---------- Previous update was at 09:12 PM ----------
kurumi,
Thank you for the help, but I would like to keep it in awk or bash if possible.