Awk script to replace null columns with blank

Shell Programming and Scripting
1

I have a file with contents

"08011"||20080812
"23348"|20080827|20080924
"23387"|20080829|20080915
"23581"|20081003|20081028
"23748"|20081017|20090114
"24095"|20080919|20081013
"24105"|20070723|20070801
"24118"|20080806|20081013
"24165"|20080820|20080912
"24221"|20080908|20080929

i want to write 10 blanks in case 2 pipes are coming together in the file.
Please help using awk script

2 
sed 's/||/|        |/g' inputfile

Or if you really want to do it in awk:

awk -F"|" '{ for (i=1;i<=NF;i++) { if ($i=="") { $i="        " } } OFS="|";print }' inputfile

or

awk '{gsub ("\\|\\|", "|        |"); print}' inputfile
3 
 
$ sed 's/\|\|/\|          \|/' test
"08011"|          |20080812
"23348"|20080827|20080924
"23387"|20080829|20080915
"23581"|20081003|20081028
"23748"|20081017|20090114
"24095"|20080919|20081013
"24105"|20070723|20070801
"24118"|20080806|20081013
"24165"|20080820|20080912
"24221"|20080908|20080929
4 
awk 'BEGIN{FS=OFS="|"}{for(i=1;++i<NF;)$i=$i?$i:"        "}1' file