awk returns an integer?

Shell Programming and Scripting
1

I need to extract a value from a text file into a ksh script, and change the last two letters to "00". awk gets the right value (2500 in this example), but the variable has no value.

I use the following command:
StartTime=expr nawk 'NR==20 {print $11;exit}' $New_FILE
echo 1 $StartTime mytime
$StartTime=`echo $StartTime | sed -n -e "s/30/00/" -e "p"`

where $New_FILE is the text file name.

What I get is:
2500
,1 mytime
Main[46]: =: not found

Thanks for your help,
Iliklev

2

Perhaps you can better post your input file and the desired output instead of a solution that doesn't work.

Regards

3

sure.
Here is the input file (without the header lines).
I need to extract a parameter $11 from line 20 and use it as a variable $StartTime in the code. (In this file it is 2500)

 NOMV TV ETIQUETTE       NI    NJ    NK \(DATE-O  h m s\)          IP1    IP2   IP3     DEET     NPAS  DTY  G   IG1   IG2   IG3   IG4

0- HSO3 P  AURV1.31WFLX   160   210     1 20070601 000000            0   2500     0      900      100  R16  N   150   200 23936 37973
1- HPXA P  AURV1.31WFLX   160   210     1 20070601 000000            0   2500     0      900      100  R16  N   150   200 23936 37973
2- RPXA P  AURV1.31WFLX   160   210     1 20070601 000000            0   2500     0      900      100  R16  N   150   200 23936 37973
3- SO4= P  AURV1.31WFLX   160   210     1 20070601 000000            0   2500     0      900      100  R16  N   150   200 23936 37973
4

Hopely is this what you mean, it assigns the 11th field of line 20 to the variable StartTime:

StartTime=$(awk 'NR==20{print $11;exit}' file)

Regards

5

Thanks Franklin52

That did the trick