awk print the next line on the current line

Shell Programming and Scripting
1

Ok I have a file with hundreds of lines, four columns, space delimited, TESTB.TXT for example
TESTB.TXT
---

AA ZZ 12 34
BB YY 56 78
CC XX 91 23
DD VV 45 67

---

I want a new file that has 7 columns, the first four are identical, and the next 3 are the last three of the next line...so for example
TESTB2.TXT
---

AA ZZ 12 34 YY 56 78
BB YY 56 78 XX 91 23
CC XX 91 23 VV 45 67
DD VV 45 67

---

I hope I typed that right and I hope the pattern is obvious. Obviously the last line of the file wont have a next line, so its last3 columns are blank. no problem there. or if you know of a similar script just point me to it and I'll hack out the details.

2

$[/tmp] > more test.txt
AA ZZ 12 34
BB YY 56 78
CC XX 91 23
DD VV 45 67

$[/tmp] > echo "" > test1.txt
$[/tmp] > more test1.txt

$[/tmp] > cat test1.txt test.txt > test2.txt
$[/tmp] > more test2.txt

AA ZZ 12 34
BB YY 56 78
CC XX 91 23
DD VV 45 67

$[/tmp] > cat test.txt | awk '{print $2 " " $3 " " $4}' > test3.txt
$[/tmp] > more test3.txt
ZZ 12 34
YY 56 78
XX 91 23
VV 45 67

$[/tmp] > paste test2.txt test3.txt > test4.txt
$[/tmp] > more test4.txt
ZZ 12 34
AA ZZ 12 34 YY 56 78
BB YY 56 78 XX 91 23
CC XX 91 23 VV 45 67
DD VV 45 67

3

With awk:

awk ' 
NR==1{printf("%s", $0);next}
{print FS $2,$3,$4;printf("%s", $0)}
END{if(!(NR%2)){print ""}}
' file

Regards

4

the paste command will work! thats perfect. I did not even know about the paste command. thank you!

5 
awk 'END{print __}{_=__}{__=$0;$1=_}_' file

Use nawk or /usr/xpg4/bin/awk on Solaris.

6

chek it this!

awk '{ print last,$0; last=$0 }' file.txt

Usefull.