awk print odd values

Shell Programming and Scripting
1 
value=$(some command)

for all in `echo $value`
do
    awk checks each value (all) to see if it is a odd number. if so, prints the value
done

sounds easy enough but i've been unable to find anything on google.

2

awk can use modulus 2 and if result is 0 it's even:

$ echo "12" | awk "$0%2"
$ echo "13" | awk "$0%2"
13

But, do you really need to use awk this can be achieved from within the shell:

for all in 2 3 4 5 6
do
   [ $((all%2)) -gt 0 ] && echo $all
done
1 Like
3

In recent shells, you could even simplify that to

for all in 2 3 4 5 6; do ((all%2)) && echo $all; done