Awk: Print count for column in a file using awk

Shell Programming and Scripting
1

Hi,
I have the following input in a file & need output as mentioned below(need counter of every occurance of field which is to be increased by 1).

Input:

919143110065
919143110065
919143110052
918648846132
919143110012
918648873782
919143110152
919143110152
919143110152
919143110152

Output:

919143110065,1
919143110065,2
919143110052,1
918648846132,1
919143110012,1
918648873782,1
919143110152,2
919143110152,3
919143110152,4
919143110152,5

present code which needs modification is as follows(it counts the uniq count). Please help

awk 'count[$1]++}END{for (i in count) print i","count}' input
2 
awk ' { arr[$0]++; print $0 "," arr[$0] } ' input
1 Like
3

I would simplify like this

$ awk '{print $0,++a[$0]}' file
1 Like