awk percentage

Shell Programming and Scripting
1

how would you calculate percentage by per line? Given a column of 16 lines, grab each line and divide it by the sum of the entire column and multiply by 100?
thanks ...

2

What have you attempted so far and and where do you get stuck?

Regards

3

well i am very new to awk. i just managed to get the sum of a field.

awk '{ for (i = 1; i <= NF; i++) s = s+$i }; END { print s /100 }'

i can remove the percentage of the whole field as one.. but i am stuck at processing the percentage for each line of that column

4

It's not really clear what your trying to achieve, can you post your input file and the desired output?

Regards

5

Input :

629
587
584

output :

34.94
16.85
16.77

(what i am doing here is taking the first line 629 divide it by sum of the field - 1800 and multiplying to give a % of 34.94)
I can get the sum of the field... like i have stated in the code.. but cannot calculate the percentage of each line of the field.

6

This is ok:

34.94 = 629/1800*100

But can you clarify this?

16.85 = <- I can't figure this out
16.77 = <- ??

Regards

7 
awk '{array[NR] = $0; sum+= $0 }
     END {
       for (x = 1; x <= NR; x++)
             printf "%2.2f\n", (100 * array[x])/sum
     }
   ' file
8

sorry they were the wrong values
32.61
32.44

i hope you are understanding what i am getting at. i need to manipulate each line and show them as percentage

9 
awk 'NR==FNR{s+=$0;next}{printf("%2.2f\n", $0/s*100}' file file

Regards