Hi,
I am having file which contains around 15 columns, i need to fetch column 3,12,14 based on the condition that column 3 starts with 40464
this is the sample data
how to achieve that
Hi,
I am having file which contains around 15 columns, i need to fetch column 3,12,14 based on the condition that column 3 starts with 40464
this is the sample data
how to achieve that
awk 'substr($3,1,5) ~ /40464/{print $3,$12,$14}' filename
cheers,
Devaraj Takhellambam
awk '$3~/^40464/{print $3,$12,$14}' filename
Hi, aemunathan:
If the data is as in your sample, spread out across 4 rows:
paste -d' ' - - - - < data | tr -s ' ' | cut -d' ' -f3,12,14 | grep ^40464
If in case the columns are all in a single row:
cut -d' ' -f3,12,14 data | grep ^40464
Regards,
Alister