awk or sed to split dn

Shell Programming and Scripting
1

Hello -

I have an input file with user dn's. e.g.

cn=peter,cn=users,dc=com,dc=uk
cn=simon,cn=users,dc=com,dc=uk
cn=john,cn=users,dc=com,dc=uk
cn=fred,cn=users,dc=com,dc=uk

My script needs to generate an LDIF file based on this input file as below:-

awk '{ FS="[=|,]"}
   {
      print "dn: " $1
      print "changetype: add"
      print "objectclass: top"
      print "changetype: person"
      print "uid: " $1
      print "mail: " $1"@com.uk"
      print "cn: " $1
      print "userpassword: " $password
}' $INFILE >> $OUTFILE

Now I can't work out what the awk statement should look like so that "dn" is assigned the full dn from the file and uid and cn are assigned just a segment. For example, the output for one line should look like:

dn: cn=peter,cn=users,dc=com,dc=uk
 changetype: add
objectclass: top
changetype: person
uid: peter
mail: peter@com.uk
cn: peter
userpassword: somepass

Clearly the above will not work. Any help much appreciated.
Many thanks

2

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Try this:

awk -F, '
{
split($1,a,"=")
print "dn: " $0
print "changetype: add"
print "objectclass: top"
print "changetype: person"
print "uid: " a[2]
print "mail: " a[2]"@com.uk"
print "cn: " a[2]
print "userpassword: " "somepass"
}' $INFILE >> $OUTFILE