awk multiply fields within lines, then total

Shell Programming and Scripting
1

Here is my scenario, I have two columns. I need to add the first columns (the easy part). The second column is a percent that I need to subtract by 100 then multiply against the first column for each line, then sum the output for a total

Here is the input:

942330863 96
942172150 95
942099452 92

I need this as an output:

2826602465 160169797

I tried this code, but it's just doing the percentage work and only doing it for the first line and not summing every line.

awk '
BEGIN {FS=","}                                                   
    NR == 1{ n1 = $1; x = substr((100-$2)/100,2,3); y = x*$1;  next }
    { n1 += $1; y += $y }
END { printf ("%-15d%d\n",n1,y) 
}'
2 
 awk 'END { printf "%d %d\n", s, p }
{ s += $1; p += (100 - $2) * $1 / 100 }
  ' infile
3 
# cat file
942330863 96
942172150 95
942099452 92
# awk 'END{printf "%d %d\n",a,b}{_=10^2;a+=$1;b+=($1/_)*(_-$2)}' file
2826602465 160169798
4

Thanks all!! I modified it just a little to multiply by a percentage. I added a printf so the large number would be printed instead of the exponential notation.

awk 'END { printf "%-15d%d\n", s, p } { s += $1; p += (100 - $2) * 0.01 * $1 }'

However, I just through some more numbers at the infile:

942330863 96
942172150 95
942099452 92
943387548 91

Gets me a result of:

3769990013     245074677

But more info my infile truncates the total in column 1:

942330863 96
942172150 95
942099452 92
943387548 91
941335230 89

result:

4.71133e+09    348621552
5

base on last sample

# awk 'END{printf "%d %d\n",a,b}{_=10^2;a+=$1;b+=($1/_)*(_-$2)}' file
3769990013 245074677

# awk --version
GNU Awk 3.1.3
Copyright (C) 1989, 1991-2003 Free Software Foundation.