awk help

Shell Programming and Scripting
1

I would like to filter out the following output:-

ps -ef | egrep "eurex|liffe"
./eurexPrice
/bin/sh
./eurexTrade
/bin/sh
/usr/bin/egrep
/bin/sh
/bin/sh
./eurexDaxTrade
/bin/sh
./eurexTrade_Tristan
./eurexTradeMM
0:05

And would like to have final output looking like this :-

eurexPrice
eurexTrade
eurexDaxTrade
eurexTrade_Tristan
eurexTradeMM

2

Hi sam,

Using awk,

ps -ef | egrep "eurex|liffe"  > out.txt
          awk '/\.\// {sub("./","",$0);print $0;}' out.txt

You can do it using sed also

ps -ef | egrep "eurex|liffe"  > out.txt
         sed '/\.\//!d;s/\.\///g' out.txt

Both will give you the required output. First we need to take the lines which starts with ./ then replace ./ with nothing.

Regards,
Chella

3

Thanks,

How about this scenario :-
liffe_trade2
./eurexPrice
ksh
liffe_trade
liffe_price
/bin/sh
ksh
/bin/sh
./eurexTrade
ksh

Would like the output as :-
liffe_trade2
eurexPrice
liffe_trade
liffe_price
eurexTrade

-sam

Thanks
-sam

4

Assuming the list already exist;
list="liffe_trade2 ./eurexPrice ksh ..."

#!/bin/ksh
list=`echo $list | egrep "eurex | liffe"`

for item in $list
do
basename $item
done

OR simply

ps -ef | egrep "eurex|liffe" | egrep "eurex|liffe" | sed 's/.\///g'

BTW, what command that produce the earlier ouput ?