AWK filter

Shell Programming and Scripting
1

Hi I am using the following to get the filename

ls -lrt filename* | tail -1 | awk {'print$9'}

o/p : filename-20101117

want to extract 20101117 from the filename ..

Pls advise

2 
ls -lrt filename* | tail -1 | awk {'print$9'} | cut -d'-' -f2
3 
ls -lrdt filename* | sed -n '$s/.*-//p'

or rather:

ls -ldt filename* | sed 's/.*-//;q'
4

the same if you want to use awk only

5 
ls -lt filename* | awk -F- 'NR==1{print $NF}'
6 
ls -lrdt filename* | awk -F- '{p=$NF}END{print p}'

---------- Post updated at 10:43 ---------- Previous update was at 10:42 ----------

Morning :smiley: :b:

7 
ls -lrt filename* | awk -F- 'NR==1{print $NF}'

the o/p comes at 20101116.txt

ls -lrt filename* | awk -F- 'NR==1{print $NF}' | cut -d'.' -f2

o/p txt

I require only 20101116 as o/p

8 
ls -lt filename* | awk -F"[-.]" 'NR==1{print $(NF-1)}'
9

thru sed..

ls -lt filename*| sed -n '1s/.*-\([0-9]\+\)\..../\1/p'