awk comparison not working

Shell Programming and Scripting
1

Can you please help me on belw awk comparsion which doest not work

 
cat employee_list
NAME Last-login
Jack 03/25/2013
Maneul 03/26/2013
Eric 03/26/2013
Samuel 03/28/2013
loak 03/29/2013
zac 03/29/2013

this is my awk .. it gives me error

cat employee_list | awk '(($2=='date +"%m/%d/%Y" -d last-monday') || ($2=='date +"%m/%d/%Y" -d last-tuesday')) {print $1}'

( date working fine)

date +"%m/%d/%Y" -d last-monday
03/25/2013

output example

Jack
Maneul
Eric
2

The date is a string, so in awk there would need to be double quotes around them if you want to compare it do $2 . Although that would work, it would be better to use awk variables (for example through the -v mechanism) to be able to use shell values inside awk..

1 Like
3 
awk '$2==d1 || $2==d2 {print$1}' d1="$(date +"%m/%d/%Y" -d last-monday)" d2="$(date +"%m/%d/%Y" -d last-tuesday)" employee_list
Jack
Maneul
Eric
1 Like
4 
while read nm dt; do [ "$dt" == "$(date -d "last-monday" +"%m/%d/%Y")" -o "$dt" == "$(date -d "last-tuesday" +"%m/%d/%Y")" ] && echo $nm; done < employee_list
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