(awk) compare files in dir with an index file

Shell Programming and Scripting
1

Using awk I have an index file which has been seperated into 5 fields. The first field contains file names. What I need to do is check to see if a file exists in my current directory that is not in the first field of my index file. If its not i print out a message.
Please help!

2

What's your shell?
With zsh/ksh93 and bash you can do something like this:

awk 'NR == FNR { f[$1]; next }
!($1 in f) { print $1,"found on filesystem, but not in list!" }
' index_file <(IFS=$'\n';printf "%s\n" *)
3

im using fedora7 terminal.......im fairly new to linux...

4

Good,
did you try it?

5 
for i in *
do
	nawk -v f="$i" 'BEGIN{n=0}
	{
		if ($1==f)
			n=1
	}
	END{
		if(n==0)
			print f":not exist"
	} ' filename
done