awk command to print multiple columns

Shell Programming and Scripting
1

Hello Team,

I have written following command which is giving output is as shown below.

bash-3.00$ grep -i startup catalina.out | tail +2 | sed -n 1p | awk -F" " '{ for (x=1; x<=5; x++) {  printf"%s\n", $x } }'
Dec
19,
2010
3:28:39
PM
bash-3.00$

I would like to modify above command to give output in below format. Can anyone help me on this?

2 
grep -i startup catalina.out | tail +2 | sed -n 1p | awk -F" " '{ for (x=1; x<=5; x++) printf("%s ", $x);printf("\n"); }'

OR

grep -i startup catalina.out | tail +2 | sed -n 1p | awk -F" " '{ print $1,$2,$3,$4,$5 }'

Setting of FS to single space is not really needed as that is default FS

3

Thanks a lot Anurag,It's really working fine.