awk command - not a valid identifier message

Shell Programming and Scripting
1

Trying to run the following awk command :

export com.mics.ara.server.tools.sch_reports.Runner.num_threads=`awk -F= '!/^#/ && /com.mics.ara.server.tools.sch_reports.Runner.num_threads/{print $2}' $BKUPDIR/env.properties`
 
-bash: export: `com.mics.ara.server.tools.sch_reports.Runner.num_threads=': not a valid identifier

but i'm getting the following error message as per above ?

2
  1. Try:
com.mics.ara.server.tools.sch_reports.Runner.num_threads=1
  1. Think about the result.
  2. Learn the basics of the shell.
3

ok my question is :

I have a value within a file :

aaa.ddd.ccc.ddd.eee.fff=5

how do I create a variable from the above line so I can pass it to another file. But I only need the value 5 as the variable.

thank you

4 
$ echo "aaa.ddd.ccc.ddd.eee.fff=5" | awk '{ split($0, A, "="); printf("var=%s\n", A[2]); }'
var=5
$
5

thank you, now if my line is this below

 
com.data.ara.reportserver.tools.sch_reports.ReportRunner.num_threads=5

how would I do this ?

6

why don't you apply the same logic as above and try out?

--ahamed

7

Exact same way. It splits on '=' so it ignores everything before the =.