awk arguments

Shell Programming and Scripting
1

Having arguments as follows

There are totally 210 error codes. I have already grep custom logs as follows
checkerr.sh

A awk '$1 == 0 || $1 ==1{print $0}' rep1.txt > success.log
B awk '$1 == 84 || $1 ==85 || $1==86 {print $0}' rep1.txt > MediaErr.log

i need all the other 205 error codes grepped to OtherErr.log excluding the above error codes

OtherErr.log = Alllogs != A && B

any way, thanks with anticipation

Note : A & B indicated here are connectors and not commands

2 
awk '! /^[0-1]$/ && ! /^8[4-6]$/ {print $0}' rep1.txt > OtherErrors.log

Success

3

hi dan,

rep1.txt

Err     Date            Time        Server       Network      Dept   Usr     Pid
1       10/10/2008   00:00:01       Server A    Class A        1001   jack   101 
6       10/10/2008   00:00:01       Server A    Class A        1002   jack   102 
85      10/10/2008   00:00:01        Server A    Class A        1004   aaa   103
84     10/10/2008   00:00:01       Server A    Class A        1001   bbb   104
96      10/10/2008   00:00:01       Server A    Class A        1001   jack   151
196    10/10/2008   00:00:01       Server A    Class A        1001   jack   161
219    10/10/2008   00:00:01       Server A    Class A        1001   jack   106
0       10/10/2008   00:00:01       Server A    Class A        1001   jack   201
1       10/10/2008   00:00:01       Server A    Class A        1001   jack   202
6       10/10/2008   00:00:01       Server A    Class A        1001   jack   109

Category A in red gives output as per the command
A awk '$1 == 0 || $1 ==1{print $0}' rep1.txt > success.log

Category B in red gives output as per the command
B awk '$1 == 84 || $1 ==85 || $1==86 {print $0}' rep1.txt > MediaErr.log

I want rest of all other lines to OtherErr.log and should exclude Cat A & B

The command given by u simply gives output of the whole file rep1.txt
awk '! /^[0-1]$/ && ! /^8[4-6]$/ {print $0}' rep1.txt > OtherErrors.log

output received

1       10/10/2008   00:00:01       Server A    Class A        1001   jack   101
6       10/10/2008   00:00:01       Server A    Class A        1002   jack   102
85      10/10/2008   00:00:01        Server A    Class A        1004   aaa  103
84     10/10/2008   00:00:01       Server A    Class A        1001   bbb   104
96      10/10/2008   00:00:01       Server A    Class A        1001   jack  151
196    10/10/2008   00:00:01       Server A    Class A        1001   jack   161
219    10/10/2008   00:00:01       Server A    Class A        1001   jack   106
0       10/10/2008   00:00:01       Server A    Class A        1001   jack   201
1       10/10/2008   00:00:01       Server A    Class A        1001   jack   202
6       10/10/2008   00:00:01       Server A    Class A        1001   jack   109
4

The basic questions are : "Why! & Why not ?"

awk -F" " '! /^[0-1] / && ! /^8[4-6]/  {print $0}' rep1.txt > OtherErrors.log

Regards,

5 
awk -F" " '! /^[0-1] / && ! /^8[4-6]/  {print $0}' rep1.txt > OtherErrors.log

the code above also did not give my result. May be i am not clear with wat i explained before, so i have given the output below, kindly check and advice

thanks

Output Needed for OtherErrors.log

6       10/10/2008   00:00:01       Server A    Class A        1002   jack   102
96      10/10/2008   00:00:01       Server A    Class A        1001   jack  151
196    10/10/2008   00:00:01       Server A    Class A        1001   jack   161
219    10/10/2008   00:00:01       Server A    Class A        1001   jack   106
6       10/10/2008   00:00:01       Server A    Class A        1001   jack   109
6

How about this:

awk '
    $1 == 0 || $1 ==1 {print > "success.log"; next }
    $1 == 84 || $1 ==85 || $1==86 { print > "MediaErr.log"; next }
    { print > "OtherErrors.log" }
' rep1.txt
7

awk '
$1 ~ /^[0-1]$/ {print $0 >> "rep1.txt"; continue }
$1 ~ /^8[4-6]$/ {print $0 >> "MediaErr.txt"; continue }
$1 ~ /^[0-9].*/ {print $0 >> "OtherErr.log" }
' 63895_awkfiler.d