Array in Shell

Shell Programming and Scripting
1

Hi, I have following issue while using Array in Shell script

I have input file as below

FILE1=filename1,filelocation1
FILE2=filename2,filelocation2
FILE3=filename3,filelocation3
FILE4=filename4,filelocation4
FILE5=filename5,filelocation5
FILE6=filename6,filelocation6

I want traverse these file and get both filename and filelocation in different variables.

Can you please help me?

2

This is straight forward and should work in both Kshell and bash. After the loop executes two arrays (indexed 0 to n-1) will exist:

i=0
sed 's/.*=//; s/,/ /' your-file  >/tmp/tfile.$$
while read a b
do
    names[$i]="$a"
    locs[$i]="$b"
    (( i++ ))
done </tmp/tfile.$$
rm /tmp/tfile.$$

The code above can be done in Kshell without using a tmp file; pipe the output from the sed directly into the while. Unfortunately that won't work in bash which is why I presented it the way I did.

This code below is more cryptic, but doesn't require the use of a tmp file to work in bash:

eval $(awk -F "[=,]" '
    {
        names = names " " $2;
        locs = locs " " $3;
    }
    END { printf( "names=( %s ); locs=( %s )", names, locs ); }
' your-input-file )
1 Like
3

And slightly tweaking agama's solution, here's without the use of temp file.

#! /bin/bash

i=0
while IFS=, read a b
do
    names[$i]=${a#*=}
    locs[$i]=$b
    (( i++ ))
done < inputfile
3 Likes
4

Thanks Agama and Balajesuri for your responses...