Array in Bash!

Shell Programming and Scripting
1

sorry I am new to the bash scripting since I was used to c shell programming. I am writting a script in bash for which I have to create an array in bash. I was able to do parse one variable through command line by doing": Lets say the below code is part of temp.bash and is called like:
temp.bash -n x -m z

 
while [ $1 ]; do
  if [ $1 == "-n" ]; then
     shift
       n=$i
   else [ $1 == "-m" ]
      shift
       name=$1
       shift
      fi
  done
echo $n
echo $name
 
O/P
x
z

I want a code such that is I pass temp.bash -n x y z -m l k z, the ouput should be
x y z
l k z
That is in an array. Currently I can only pass one character. Can anybody help?
Thanks in advance

2

A string with spaces in it is not the same thing as an array.

I don't think your if-statement if [ $1 ] does precisely what you think it does.

I'd take a slightly different approach:

WHERE=""
# $# is the number of arguments.
# While the number of arguments is greater than 0, keep looping.
while [ "$#" -gt 0 ]
do
        case "$1" in
        -n)    WHERE="n"             ;;
        -m)    WHERE="name"          ;;

        *) # All other arguments

                case "$WHERE" in
                n)        n="$n $1"     ;;
                name)   name="$name $1" ;;
                *)        ;;
                esac

                ;;
        esac

        shift
done
3

Thanks Corona688. I used the code but I am getting syntax error near unexpected token `"$WHERE"`
case "$WHERE" in
It might be verbose but I thought I will write it again what I used"

WHERE=""
 while ["$#" -gt 0 ]
 do
         case "$1" in
          -n)  WHERE="n"  ;;
          -m)  WHERE="name" ;;
              case "$WHERE" in
               n)   n="$n $1"
             name) name="$name $1"
              esac
           ;;
           esac
           shift
done
echo $n
echo $name

when I type temp.bash with this code like: temp.bash -n x y -m l k, I am expecting to get result:
x y
l k
instead I get the error message describe above.

4

You forgot a line:

        *) # All other arguments

That's not pseudocode. The * accepts all arguments that weren't matched by -n or -m before it.

Also, you left some important spaces out of your while-statement:

while ["$#" -gt 0 ] # Wrong
while [ "$#" -gt 0 ] # Right
5

A space is required (non-optional) between [ and "

while [ "$#" -gt 0 ]

-----------------------------------------------------------
Corona688 has already answered.

6

Thanks Corona668. The while loop of not using space was a typo but the problem was using not using :

*) # All other arguments

Thanks once again.