Alter existing script to work with longer file name

Shell Programming and Scripting
1

I have this script:

#!/bin/sh

for file in "$@"
do
        ext=${file##*.}
        base=${file%.*}
        num=${base##*v}
        zeroes=${num%%[!0]*}
        num=${num#$zeroes}      #remove leading zeros, or it uses octal
        num=$((num+1))
        base=${base%v*}
        new=$(printf '%sv%04d.%s' "$base" "$num" "$ext")
        cp -nv "$file" "$new"
done

It works great with file names that are xxx_xxx_v001.aep, but it won't work on this: xxx_xxx_v001_001.aep.

I've tried and tried but just can't figure out why it won't work.
Any help is much appreciated.
Thanks.

2

I assume you still want to increment the Vnnn part on the 2nd longer filename.

Also note you can use 10# to avoid the octal issue:

for file in "$@"
do
        ext=${file##*.}
        base=${file%.*}
        num=${base##*v}
        rest=${num#*_}
        if [ ${#rest} -eq ${#num} ]
        then
            rest=""
        else
            num=${num%%_*}
            rest=_$rest
        fi
        num=$((10#$num+1))
        base=${base%v*}
        new=$(printf '%sv%04d%s.%s' "$base" "$num" "$rest" "$ext")
        echo cp -nv "$file" "$new"
done
1 Like
3

That works but changes the first number.
I need one that changes the last number and ignores the first.

So, 093_180_v001_004.aep ; would become 093_180_v001_005.aep

The thing is that the first number will not always be v001 ...

Doable?

4

OK that is actually a little easier:

for file in "$@"
do
        ext=${file##*.}
        base=${file%.*}
        num=${base##*[v_]}
        base=${base%$num}
        num=$((10#$num+1))
        new=$(printf '%s%03d.%s' "$base" "$num" "$ext")
        cp -nv "$file" "$new"
done
5

Yes! That works perfectly. Thank you!