Add new parameters into a line, and redirect the line to other file

Shell Programming and Scripting
1

How can i add new parameters into a line, and redirect the line to other file?

For example:
1.sh

name:owner
google:richard
youtube:student

I want a, for example 2.sh with:

name:owner:description
google:richard:search site
youtube:student:video site

In the 2.sh, I added a new column: description and the parametrs.

I have builded a function to add things into file like:
addreg "$name:$owner"


addreg() {
    local key=$(echo "$1" | cut -d $SEP -f1)                     
    if existe "$key"; then
        echo "Error! The key '$key' is on the file"
        return 1
    else                                                             # new key
        echo "$*" >> "$c"                                 # save registry
        echo "Added '$key'!"
    fi
    return 0
}

I tried to make this but i cant get the result. The way I found to avoid this, is to put into the original file the fields like google:richard:description and when I want to insert the description I search the words description and edit to the $description that I insert.

Hope you can understand my english;)

---------- Post updated at 05:40 PM ---------- Previous update was at 03:15 PM ----------

Can anyone help me?

2

I'm sure there's much more to your process than you've listed; for example, I don't see where you're getting the third column's contents...and your function's $c.

However, please note:

1) Probably a Typo in your "if" statement (existe should be exists...?);

2) Assuming you're getting your third column contents from somewhere:

$ tail -3 file_test.txt |while read LINE ;do print "$LINE:$LINENO" ;done
name:owner:1
google:richard:1
youtube:student:1
3

the $c is where the data is, like $c=file.txt.

The third column is asked to the user, with a echo "add description" read description.

I dont know how I can add a third column in the line. I think, this might result. I will test and thank you!

---------- Post updated at 09:24 PM ---------- Previous update was at 09:19 PM ----------

The tail function is perfect i think. But the number -3 is the number of lines that will be extracted. How can i check the number when i dont know how many lines are in the file? Use a counter right? and if I wanna extract a certain line like the line with $name google. How can i do that?

---------- Post updated at 09:25 PM ---------- Previous update was at 09:24 PM ----------

Tail is a great anyway!

tail MAN Page

4

tail was just an example to dump the file. You can use anything; head, tail, more, grep...

5

if I wanna extract a certain line like the line with $name google. How can i do that?

6

grep is your friend in that case.

Regards

7

program.sh

source functions.sh
...

if exists "$name";then
	move "$name"
else
	echo "Error: name not here in $c"
fi

...

functions.sh


$c=1.txt
$v=2.txt

# it checks if $1 is in the file
exists() {
	grep -i -q "^$1$SEP" "$c"
}

#insert info in 2.txt

insert_in_2() {
	local chave=$(echo "$1" | cut -d $SEP -f1)                         

	if exists "$key"; then
		echo "The key '$key' is reg in <1.sh>."
		return 1
	else                                         	                      # new key
		echo "$*" >> "$v"                     			      
		echo "Reg '$chave' added with sucess in <2.txt>."
	fi
	return 0
}

#delete the line in 1.txt and moves the line to 2.txt
move(){
	exists $1 || return
	echo -n "Insert description "
	read description
	
	aux="$(grep -i -v "$name" "1.txt")"  
	insert_in_2 "$aux:$description"
	echo
	echo "The description in '$1' added with sucess!"
		}

This is my code, but it copy the all lines in 1.txt but I only want the line that $name is in! How can i do that?

8

grep -v explicitly excludes $name...drop the -v.