Add 'ENDEND' on end of each record at position is 14-20

Shell Programming and Scripting
1

I have file format like below and I'm trying to modify this file.
I need to add 'ENDEND' end of each record.

01 ASH01 1CTCTL EDPPOO STAND
01 ASH08 0020 A1TH 101
01 ASH09 0022 A1TH 102
01 ASH09 0022 A1TH 103
01 ASH02 2CTCTL EDPPOO STAND
01 ASH08 0030 A1TH 201
01 ASH09 0042 A1TH 302
01 ASH09 0052 A1TH 403
01 ASH03 1CTCTL EDPPOO STAND
01 ASH08 0020 A1TH 401
01 ASH09 0022 A1TH 502
01 ASH09 0022 A1TH 603

Result file should look like :

01 ASH01 1CTCTL EDPPOO STAND
01 ASH08 0020 A1TH 101
01 ASH09 0022 A1TH 102
01 ASH09 0022 A1TH 103
ENDEND
01 ASH02 2CTCTL EDPPOO STAND
01 ASH08 0030 A1TH 201
01 ASH09 0042 A1TH 302
01 ASH09 0052 A1TH 403
ENDEND
01 ASH03 1CTCTL EDPPOO STAND
01 ASH08 0020 A1TH 401
01 ASH09 0022 A1TH 502
01 ASH09 0022 A1TH 603
ENDEND
ENDEND

2

How do you know where one record ends and the other begins...is there something that can uniquely identify each record.

3 
awk '/STAND$/ && NR>1{print "ENDEND"}{print}END{printf("%s\n%s\n","END","END"}' file > newfile

Regards

4

based on "1CTCTL" this means header record and rest are lines...
I would like to print end of each record (at position 14 - 20) "ENDEND".

1 Record means: Header row and line rows.

5 
cat file | sed '/EDPPOO/ i\
ENDEND
'
6

but this will add ENDEND in first line also..
i mean
ENDEND
01 ASH01 1CTCTL EDPPOO STAND
01 ASH08 0020 A1TH 101
01 ASH09 0022 A1TH 102
01 ASH09 0022 A1TH 103
ENDEND
01 ASH02 2CTCTL EDPPOO STAND
01 ASH08 0030 A1TH 201
01 ASH09 0042 A1TH 302
01 ASH09 0052 A1TH 403
ENDEND
01 ASH03 1CTCTL EDPPOO STAND
01 ASH08 0020 A1TH 401
01 ASH09 0022 A1TH 502
01 ASH09 0022 A1TH 603