Access another variable config variable

Shell Programming and Scripting
1

Hi all, Please help me on my problem.
I want to take a value of variable which the variable is in other file.

variable.sh

wesly=1
wina=2
wekin=3

variabletaker.sh

source variable.sh

echo $wesly

when i run the variabletaker.sh
the error result is like here

error

source: variable.sh: file not found

Thank before..

i am working on /bin/bash

2

Hi

Are the files in the same path?
If not, either put them in the same, or considider putting relative or absolute paths in front of the filenames.

Hope this helps

3

Try:-

source ./variable.sh

OR

source /full/path/to/variable.sh

Ensure permissions are set correctly for 'variable.sh'...

4

Thank you Mr Wisecracker.
Your suggest is worked.

When I work in sh shell I actually succes without

.\

before the file name.
:b::).