Working with a filename

Shell Programming and Scripting
1

Hello,

I am trying to work with filename in Unix.
So in my example a have a filename like : ABC_totoalerte.txt and I want just to capture totoalerte.txt.

How can i do it , i check it with cut -c,4-* but it didn't work.

Can you help me about this problem. Thanks..

2

This solution is very specific to the format you gave i.e. ABC_anyfilename.extension

echo ABC_totoalerte.txt | awk -F"_" '{ printf $2 }'

Vino

3

Try This

But this is also for a specific structure :-

sed 's/^[a-z]*\_\([a-z]*[0-9]*[.][a-z]*\)/\1/' file.txt

4

:slight_smile:
echo ABC_totoalerte.txt | cut -d"_" -f2

should work.

5

Use a good shell (ksh, bash) and then use the shell's built-in features to do this lightning-fast...

$ FILENAME="ABC_totoalerte.txt"
$ FILENAME=${FILENAME##*_}
$ echo $FILENAME
totoalerte.txt

Cheers
ZB

6

If you always want to get the last part after '_' do this


ls -1 | cut -d "_" -f2